If $a$ and $b$ are the position vectors of $A$ and $B$ respectively,then the position vector of a point $C$ on $AB$ produced such that $\overrightarrow{AC} = 3\overrightarrow{AB}$ is

  • A
    $3a - b$
  • B
    $3b - a$
  • C
    $3a - 2b$
  • D
    $3b - 2a$

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Let $\vec{a}=\hat{i}+2 \hat{j}+3 \hat{k}$,$\vec{b}=2 \hat{i}+3 \hat{j}-5 \hat{k}$ and $\vec{c}=3 \hat{i}-\hat{j}+\lambda \hat{k}$ be three vectors. Let $\vec{r}$ be a unit vector along $\vec{b}+\vec{c}$. If $\vec{r} \cdot \vec{a}=3$,then $3 \lambda$ is equal to :

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